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TS EAMCET · Chemistry · Structure of Atom

The energy of an electromagnetic radiation is \(19.875 \times 10^{-13}\) ergs. What is its wave number in \(\mathrm{cm}^{-1}\) ? \(\left(h=6.625 \times 10^{-27}\right.\) erg sec, \(\left.c=3 \times 10^{10} \mathrm{~cm} \mathrm{sec}^{-1}\right)\)

  1. A \(1000\)
  2. B \(10^6\)
  3. C \(100\)
  4. D \(10000\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(10000\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & E=h v=h \times \frac{c}{\lambda}=h \times c \cdot \bar{v} \\ & \therefore \quad \bar{v}=\frac{E}{h c}=\frac{19.875 \times 10^{-13}}{6.625 \times 10^{-27} \times 3 \times 10^{10}}=10^4\end{aligned}\)