TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The correct increasing order of ionisation enthalpy of \(\mathrm{He}, \mathrm{Li}^{+}, \mathrm{Be}^{2+}\) is
- A \(\mathrm{He} < \mathrm{Li}^{+} < \mathrm{Be}^{2+}\)
- B \(\mathrm{Be}^{2+} < \mathrm{Li}^{+} < \mathrm{He}\)
- C \(\mathrm{Li}^{+} < \mathrm{Be}^{2+} < \mathrm{He}\)
- D \(\mathrm{Be}^{2+} < \mathrm{He} < \mathrm{Li}^{+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{He} < \mathrm{Li}^{+} < \mathrm{Be}^{2+}\)
Step-by-step Solution
Detailed explanation
Be electronic configuration \(=1 s^2 2 s^2\) Li electronic configuration \(=1 s^2 2 s^1\) He electronic configuration \(=1 s^2\) For ions with 2-electrons, more be the \(Z_{\text {(charge proton) }}\) ratio, more is the ionisation enthalpy. e charge electron) \(\frac{Z}{e}\) for…
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