TS EAMCET · Chemistry · Redox Reactions
\(\mathrm{KMnO}_4\) reacts with \(\mathrm{KI}\), in basic medium to form \(\mathrm{I}_2\) and \(\mathrm{MnO}_2\). When \(250 \mathrm{~mL}\) of \(0.1 \mathrm{M} \mathrm{KI}\) solution is mixed with \(250 \mathrm{~mL}\) of \(0.02 \mathrm{M}\) \(\mathrm{KMnO}_4\) in basic medium, what is the number of moles of \(\mathrm{I}_2\) formed?
- A \(0.015\)
- B \(0.0075\)
- C \(0.005\)
- D \(0.01\)
Answer & Solution
Correct Answer
(B) \(0.0075\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{r}\lceil\text {-factor }=1 \longrightarrow \\ \mathrm{MnO}_4^{-}+\mathrm{I}^{-} \rightleftharpoons \mathrm{MnO}_2+\mathrm{I}_2 \\ \bigsqcup_{n \text {-factor }=3}^{\rightleftharpoons}\end{array}\) Number of milli equivalents of…
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