TS EAMCET · Chemistry · Thermodynamics (C)
Calculate \(\Delta H^{\circ}\) for the reaction, \(\mathrm{Na}_2 \mathrm{O}(\mathrm{s})+\mathrm{SO}_3(\mathrm{~g}) \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4(\mathrm{~g})\) given the following :
- A +823 kJ
- B –581 kJ
- C –435 kJ
- D +531 kJ
Answer & Solution
Correct Answer
(B) –581 kJ
Step-by-step Solution
Detailed explanation
By ' \(2 A+\frac{C}{2}-B\) ', we get \(\begin{aligned} & \mathrm{Na}_2 \mathrm{O}+\mathrm{SO}_3 \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4 \\ & \Delta H=-2 \times 146+\frac{259}{2}-418 \\ & \text { or } \quad \Delta H=-580.5 \approx-581 \mathrm{~kJ} \end{aligned}\)
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