ExamBro
ExamBro
TS EAMCET · Chemistry · Chemical Equilibrium

At \(550 \mathrm{~K}\), the \(K_c\) for the following reaction is \(10^4 \mathrm{~mol}^{-1} \mathrm{~L} X(g)+Y(g) \rightleftharpoons Z(g)\) At equilibrium, it was observed that \([X]=\frac{1}{2}[Y]=\frac{1}{2}[Z]\) What is the value of [Z] (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) at equilibrium?

  1. A \(2 \times 10^{-4}\)
  2. B \(10^{-4}\)
  3. C \(2 \times 10^4\)
  4. D \(10^4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \times 10^{-4}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & X(g)+Y(g) \rightleftharpoons Z(g) \\ & K_c=\frac{[Z]}{[X][Y]} \text { or } 10^4=\frac{[Z]}{[X][Y]} \\ & \therefore \quad[Z]=10^4[X][Y]=10^4 \times \frac{1}{2}[Z][Z] \\ & \text { (Given, }[X]=\frac{1}{3}[Y]=\frac{1}{2}[Z] \text { ) } \\ & \therefore \quad[Z]=2…