TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
Arrange the following ions in the correct order with respect to their ionic radii.
- A \(\mathrm{Br}^{-}>\mathrm{Cl}^{-}>\mathrm{Na}^{+}>\mathrm{Be}^{2+}\)
- B \(\mathrm{Be}^{2+}>\mathrm{Na}^{+}>\mathrm{Cl}^{-}>\mathrm{Br}^{-}\)
- C \(\mathrm{Cl}^{-}>\mathrm{Br}^{-}>\mathrm{Na}^{+}>\mathrm{Be}^{2+}\)
- D \(\mathrm{Na}^{+}>\mathrm{Be}^{2+}>\mathrm{Br}^{-}>\mathrm{Cl}^{-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Br}^{-}>\mathrm{Cl}^{-}>\mathrm{Na}^{+}>\mathrm{Be}^{2+}\)
Step-by-step Solution
Detailed explanation
The electronic configuration of \(\mathrm{Be}^{2+}\) is \(\left[{ }_2 \mathrm{He}\right], \mathrm{Na}^{+}\)is \(\left[{ }_{10} \mathrm{Ne}\right], \mathrm{Cl}^{-}\)is \(\left[{ }_{18} \mathrm{Ar}\right]\) and \(\mathrm{Br}^{-}\) is \(\left[{ }_{36} \mathrm{Kr}\right]\). We know,…
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