TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
\(\begin{aligned} & \mathrm{XeF}_4+\mathrm{O}_2 \mathrm{~F}_2 \rightarrow \mathrm{X}+\mathrm{O}_2 \ & \mathrm{X}+\underset{(1 \mathrm{~mole})}{\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Y}+2 \mathrm{HF}}\end{aligned}\) The shapes of molecules of \(x\) and \(y\) respectively are:
- A Square planar, square pyramidal
- B Distorted octahedral, square pyramidal
- C Distorted tetrahedral Distorted octahedral
- D Square pyramidal, Tetrahedral
Answer & Solution
Correct Answer
(B) Distorted octahedral, square pyramidal
Step-by-step Solution
Detailed explanation
\(\mathrm{XeF}_4+\mathrm{O}_2 \mathrm{~F}_2 \rightarrow \mathrm{XeF}_6+\mathrm{O}_2\) (x) \[ \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{XeOF}_4+2 \mathrm{HF} \] (1 mole) (y) \(\mathrm{XeF}_6=\) distorted octahedral shape. \(\mathrm{XeOF}_4=\) Square pyramidal…
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