TS EAMCET · Chemistry · Chemical Kinetics
A particular reaction has a rate constant \(1.15 \times 10^{-3} \mathrm{~s}^{-1}\). How long does it take for \(6 \mathrm{~g}\) of the reactant of reduce to \(3 \mathrm{~g}\) ? \((\log 2=0.301)\)
- A \(301 \mathrm{~s}\)
- B \(603 \mathrm{~s}\)
- C \(840 \mathrm{~s}\)
- D \(15 \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(603 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given, rate constant \((k)=1.15 \times 10^{-3} \mathrm{~s}^{-1}\) Reaction time \(=\) ? Initial amount of reactant \(\left(A_o\right)=6 \mathrm{~g}\) Final amount of reactant \(\left(A_f\right)=3 \mathrm{~g}\) From rate constant equation,…
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