TS EAMCET · Chemistry · Electrochemistry
0.592 g of copper is deposited in 60 minutes by passing 0.5 amperes current through a solution of copper (II) sulphate. The electro chemical equivalent of copper (II) (in \(\mathrm{g} \mathrm{C}^{-1}\) ) is \(\left(\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}\right)\)
- A \(3.3 \times 10^{-3}\)
- B \(3.3 \times 10^{-4}\)
- C \(6.6 \times 10^{-3}\)
- D \(6.6 \times 10^{-4}\)
Answer & Solution
Correct Answer
(B) \(3.3 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { According to Faraday law, } \\ & \mathrm{W}=\mathrm{Zit} \\ & \mathrm{Z}=\text { electro chemical equivalent } \\ & \text { given, } \\ & \mathrm{W}=0.592 \mathrm{~g} \\ & \mathrm{t}=60 \text { minutes } \\ & =60 \times 60 \mathrm{~s} \\ & =3600…
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