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NEET · Physics · STD 12 - 12. atoms
When an \(\alpha -\)particle of mass \(m\) moving with velocity \(v\) bombards on a heavy nucleus of charge \(Z_e\) , its distance of closest approach from the nucleus depends on \(m\) as
- A \(\frac{1}{{{m^2}}}\)
- B \(m\)
- C \(\frac{1}{m}\)
- D \(\frac{1}{{\sqrt m }}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{m}\)
Step-by-step Solution
Detailed explanation
Distance of closest approach when an \(\alpha\) particle of mass \(m\) moving with velocity \(v\) is bombarded on a heavy nucleus of charge \(Z e,\) is given by \(r_{0}=\frac{Z e^{2}}{\pi \varepsilon_{0} m v^{2}} \) \(\therefore r_{0} \propto \frac{1}{m}\)
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