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NEET · Physics · STD 11 - 3.2 motion in plane
When an object is shot from the bottom of a long smooth inclined plane kept at an angle \(60^{\circ}\) with horizontal. it can travel a distance \(\mathrm{x}_{1}\) along the plane. But when the inclination is decreased to \(30^{\circ}\) and the same object the shot with the same velocity, it can travel \(x_{2}\) distance. Then \(x_{1}: x_{2}\) will be
- A \(1: \sqrt{2}\)
- B \(\sqrt{2}: 1\)
- C \(1: \sqrt{3}\)
- D \(1: 2 \sqrt{3}\)
Answer & Solution
Correct Answer
(C) \(1: \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(v^{2}=u^{2}-2 a s\) \(\Rightarrow \mathrm{s}=\frac{\mathrm{u}^{2}}{2 \mathrm{a}}=\frac{\mathrm{u}^{2}}{2 \mathrm{gsin} \theta}\)
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