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NEET · Physics · STD 12 - 11. Dual nature of radiation and matter
When a metallic surface is illuminated with radiation of wavelength \(\lambda\) , the stopping potential is \(V.\) If the same surface is illuminated with radiation of wavelength \(2\lambda\), the stopping potential is \(\frac{V}{4}\). The threshold wavelength for the metallic surface is
- A \(5\lambda\)
- B \(\frac{5}{2}\lambda \)
- C \(3\lambda\)
- D \(4\lambda\)
Answer & Solution
Correct Answer
(C) \(3\lambda\)
Step-by-step Solution
Detailed explanation
According to Einstein's photoelectric equation, \(e V_{s}=\frac{h c}{\lambda}-\frac{h c}{\lambda_{0}}\)
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