NEET · Physics · STD 12 - 4. Moving charges and magnetism
Two very long, straight, parallel conductors \(A\) and \(B\) carry current of \(5\,A\) and \(10\,A\) respectively and are at a distance of \(10\,cm\) from each other. The direction of current in two conductors is same. The force acting per unit length between two conductors is: \(\left(\mu_0=4 \pi \times 10^{-7}\right.\) SI unit)
- A \(2 \times 10^{-4}\,Nm ^{-1}\) and is attractive
- B \(2 \times 10^{-4}\,Nm ^{-1}\) and is repulsive
- C \(1 \times 10^{-4}\,Nm ^{-1}\) and is attractive
- D \(1 \times 10^{-4}\,Nm ^{-1}\) and is repulsive
Answer & Solution
Correct Answer
(C) \(1 \times 10^{-4}\,Nm ^{-1}\) and is attractive
Step-by-step Solution
Detailed explanation
\(\frac{ F _{ M }}{\ell}=\frac{\mu_0 i _1 i _2}{2 \pi r }\) \(=\frac{4 \pi \times 10^{-7} \times 5 \times 10}{2 \pi \times 0.1}=10^{-4}\,N / m\)


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