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NEET · Physics · STD 12 - 4. Moving charges and magnetism
Two toroids \(1\) and \(2\) have total number of tums \(200\) and \(100 \) respectively with average radii \(40\; \mathrm{cm}\) and \(20 \;\mathrm{cm}\) respectively. If they carry same current \(i,\) the ratio of the magnetic flelds along the two loops is
- A \(1:1\)
- B \(4:1\)
- C \(2:1\)
- D \(1:2\)
Answer & Solution
Correct Answer
(A) \(1:1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{B}=\frac{\mu_{0} \mathrm{N}_{\mathrm{i}}}{2 \pi \mathrm{r}}\) \(\frac{\mathrm{B}_{1}}{\mathrm{B}_{2}}=\frac{\mathrm{N}_{1}}{\mathrm{N}_{2}} \frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}=\left(\frac{200}{100}\right)\left(\frac{20}{40}\right)=1: 1\)
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