NEET · Physics · STD 11 - 9.1 fluid mechanics
Two small spherical metal balls, having equal masses, are made from materials of densities \(\rho_{1}\) and \(\rho_{2}\left(\rho_{1}=8 \rho_{2}\right)\) and have radii of \(1\; \mathrm{mm}\) and \(2\; \mathrm{mm}\), respectively. They are made to fall vertically (from rest) in a viscous medum whose coefficient of viscosity equals \(\eta\) and whose denstry is \(0.1 \mathrm{\rho}_{2} .\) The ratio of their terminal velocitites would be
- A \(\frac{79}{72}\)
- B \(\frac{19}{36}\)
- C \(\frac{39}{72}\)
- D \(\frac{79}{36}\)
Answer & Solution
Correct Answer
(D) \(\frac{79}{36}\)
Step-by-step Solution
Detailed explanation
\(v_{T}=\frac{2 r^{2}(\sigma-\rho) g}{9 \eta}\) \(\frac{v_{1}}{v_{2}}=\left(\frac{r_{1}}{r_{2}}\right)^{2} \frac{\left(\sigma_{1}-\rho\right)}{\left(\sigma_{2}-\rho\right)}\)\(=\left(\frac{1}{2}\right)^{2}\left(\frac{8 \rho_{2}-0.1 \rho_{2}}{\rho_{2}-0.1 \rho_{2}}\right)\)\(=\frac{79}{36}\)
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