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NEET · Physics · STD 12 - 1. Electric charges and fields
Two point charges \(A\) and \(B\), having charges \(+Q\) and \(- Q\) respectively, are placed at certain distance apart and force acting between them is \(\mathrm{F}\). If \(25 \%\) charge of \(A\) is transferred to \(B\), then force between the charges becomes
- A \(F\)
- B \(\frac{9 \mathrm{F}}{16}\)
- C \(\frac{16 \mathrm{F}}{9}\)
- D \(\frac{4 \mathrm{F}}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{9 \mathrm{F}}{16}\)
Step-by-step Solution
Detailed explanation
\(F=\frac{-kq^2}{r^2}\) \(25 \%\) charge from \(A\) is transferred to \(B\)
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