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NEET · Physics · STD 11 - 3.2 motion in plane
Two particles \(A\) and \(B\) are moving in uniform circular motion in concentric cirdes of radius \(r_{A}\) and \(r_{B}\) with speed \(v_A\) and \(v_B\) respectively. The time period of rotation is the same. The ratio of angular speed of \(A\) to that of \(B\) will be
- A \(\mathrm{r}_{\mathrm{A}}: \mathrm{r}_{\mathrm{B}}\)
- B \({v}_{{A}}: {v}_{{B}}\)
- C \(\mathrm{r}_{\mathrm{B}}: \mathrm{r}_{\mathrm{A}}\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}_{\mathrm{A}}=\mathrm{T}_{\mathrm{B}}\) \(\Rightarrow \frac{2 \pi}{\omega_{A}}=\frac{2 \pi}{\omega_{B}}\)
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