NEET · Physics · STD 11 - 14. waves and sound
Two open organ pipes of fundamental frequencies \(n_{1}\) and \(n_{2}\) are joined in series. The fundamental frequecny of the new pipe so obtained will be
- A \(\frac{{{n_1} + {n_2}}}{2}\)
- B \(\sqrt {{n_1}^2 + {n_2}^2} \)
- C \(\;\frac{{{n_1}{n_2}}}{{{n_1} + {n_2}}}\)
- D \(\;({n_1} + n_2)\)
Answer & Solution
Correct Answer
(C) \(\;\frac{{{n_1}{n_2}}}{{{n_1} + {n_2}}}\)
Step-by-step Solution
Detailed explanation
Fundamental frequency of an open pipe of length \(L\) is given by \(n =\frac{ v }{2 L }\) \(\Longrightarrow L =\frac{ v }{2 n }\) So, we get lengths of two open pipes as \(L _{1}=\frac{ v }{2 n _{1}}\) and \(L _{2}=\frac{ v }{2 n _{2}}\) Now the pipes are join in series.
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