NEET · Physics · STD 11 - 6. system of particles and rotational motion
Two objects of mass \(10\,kg\) and \(20\,kg\) respectively are connected to the two ends of a rigid rod of length \(10\,m\) with negligible mass. The distance of the center of mass of the system from the \(10\,kg\) mass is :
- A \(\frac{20}{3}\,m\)
- B \(10\,m\)
- C \(5\,m\)
- D \(\frac{10}{3}\,m\)
Answer & Solution
Correct Answer
(A) \(\frac{20}{3}\,m\)
Step-by-step Solution
Detailed explanation
\(X _{ CM }=\frac{20 \times 10}{20+10}=\frac{20}{3} m\)
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