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NEET · Physics · STD 12 - 2. Electric potential and capacitance
Two metal spheres, one of radus \(R\) and the other of radius \(2 R\) respectively have the same surface charge density \(\sigma\). They are brought in contact and separated. What will be the new surface charge densities on them?
- A \(\sigma_{1}=\frac{5}{6} \sigma, \sigma_{2}=\frac{5}{2} \sigma\)
- B \(\sigma_{1}=\frac{5}{2} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)
- C \(\sigma_{1}=\frac{5}{2} \sigma, \sigma_{2}=\frac{5}{3} \sigma\)
- D \(\sigma_{1}=\frac{5}{3} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)
Answer & Solution
Correct Answer
(D) \(\sigma_{1}=\frac{5}{3} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)
Step-by-step Solution
Detailed explanation
Total charge \(=\sigma \times 4 \pi R^{2}+\sigma \times 4 \pi(2 R)^{2}=20 \mathrm{\sigma \pi R}^{2}\) \(\frac{\mathrm{Q}_{\mathrm{A}}}{\mathrm{Q}_{\mathrm{B}}}=\frac{1}{2}\)
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