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NEET · Physics · STD 12 - 2. Electric potential and capacitance

Two metal spheres, one of radus \(R\) and the other of radius \(2 R\) respectively have the same surface charge density \(\sigma\). They are brought in contact and separated. What will be the new surface charge densities on them?

  1. A \(\sigma_{1}=\frac{5}{6} \sigma, \sigma_{2}=\frac{5}{2} \sigma\)
  2. B \(\sigma_{1}=\frac{5}{2} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)
  3. C \(\sigma_{1}=\frac{5}{2} \sigma, \sigma_{2}=\frac{5}{3} \sigma\)
  4. D \(\sigma_{1}=\frac{5}{3} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\sigma_{1}=\frac{5}{3} \sigma, \sigma_{2}=\frac{5}{6} \sigma\)

Step-by-step Solution

Detailed explanation

Total charge \(=\sigma \times 4 \pi R^{2}+\sigma \times 4 \pi(2 R)^{2}=20 \mathrm{\sigma \pi R}^{2}\) \(\frac{\mathrm{Q}_{\mathrm{A}}}{\mathrm{Q}_{\mathrm{B}}}=\frac{1}{2}\)
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