NEET · Physics · STD 11 - 13. oscillations
Two identical point masses P and Q , suspended from two separate massless springs of spring constants \(k _1\) and \(k _2\), respectively, oscillate vertically. If their maximum speeds are the same, the ratio \(\left(A_Q / A_P\right)\) of the amplitude \(A_Q\) of mass \(Q\) to the amplitude \(A_P\) of mass \(P\) is _______.
- A \(\frac{k_2}{k_1}\)
- B \(\frac{ k _1}{ k _2}\)
- C \(\sqrt{\frac{k_2}{k_1}}\)
- D \(\sqrt{\frac{ k _1}{ k _2}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{ k _1}{ k _2}}\)
Step-by-step Solution
Detailed explanation
\(\text {Given } m_P=m_Q \)
\( \text {Also }\left(V_{\max }\right)_P=\left(V_{\max }\right)_Q \)
\( \therefore A_P \omega_P=A_Q \omega_Q \)
\( A_P \sqrt{\frac{k_1}{m_P}}=A_Q \sqrt{\frac{k_2}{m_Q}}\left[\because \omega=\sqrt{\frac{k}{m}}\right] \)
\( \therefore \frac{A_Q}{A_P}=\sqrt{\frac{k_1}{k_2}}\)
\( \text {Also }\left(V_{\max }\right)_P=\left(V_{\max }\right)_Q \)
\( \therefore A_P \omega_P=A_Q \omega_Q \)
\( A_P \sqrt{\frac{k_1}{m_P}}=A_Q \sqrt{\frac{k_2}{m_Q}}\left[\because \omega=\sqrt{\frac{k}{m}}\right] \)
\( \therefore \frac{A_Q}{A_P}=\sqrt{\frac{k_1}{k_2}}\)
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