NEET · Physics · STD 12 -6. Electromagnetic induction
Two conducting circular loops of radii \(R_{1}\) and \(\mathrm{R}_{2}\) are placed in the same plane with their centres coinciding. If \(R_{1}>>R_{2}\), the mutual inductance \(M\) between them will be directly proportional to:
- A \(\frac{R_{1}}{R_{2}}\)
- B \(\frac{R_{2}}{R_{1}}\)
- C \(\frac{\mathrm{R}_{1}^{2}}{\mathrm{R}_{2}}\)
- D \(\frac{\mathrm{R}_{2}^{2}}{\mathrm{R}_{1}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{R}_{2}^{2}}{\mathrm{R}_{1}}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{M}=\frac{\mathrm{N}_{2} \phi_{2}}{\mathrm{I}_{1}}\) \(\mathrm{M}=\frac{\mathrm{N}_{2} \mathrm{~B}_{1} \mathrm{~A}_{2}}{\mathrm{I}_{1}}\)
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