NEET · Physics · STD 11 - 4.1 newtons laws of motion
Two bodies of mass \(4 \,kg\) and \(6\, kg\) are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity \((g)\) is

- A \(\frac{g}{10}\)
- B \(g\)
- C \(\frac {g} {2}\)
- D \(\frac {g} {5}\)
Answer & Solution
Correct Answer
(D) \(\frac {g} {5}\)
Step-by-step Solution
Detailed explanation
\(a=\frac{\left(m_{2}-m_{1}\right) g}{m_{1}+m_{2}}\) \(a=\frac{(6-4) g}{6+4}-\frac{2 g}{10}\)
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