NEET · Physics · STD 11 - 6. system of particles and rotational motion
Three identical spheres, each of mass \(M ,\) are placed at the corners of a right angle triangle with mutually perpendicular sides equal to \(2 \;m\) (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin, find the position vector of centre of mass.

- A \(\frac{4}{3}(\hat{i}+\hat{j})\)
- B \(2(\hat{i}+\hat{j})\)
- C \((\hat{i}+\hat{j})\)
- D \(\frac{2}{3}(\hat{i}+\hat{j})\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{3}(\hat{i}+\hat{j})\)
Step-by-step Solution
Detailed explanation
\(x_{c m}=\frac{M \times 0+M \times 0+M \times 2}{3 M}=\frac{2}{3}\) \(y_{c m}=\frac{M \times 0+M \times 0+M \times 2}{3 M}=\frac{2}{3}\)
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