NEET · Physics · STD 12 - 11. Dual nature of radiation and matter
The threshold frequency of a photoelectric metal is \(\nu_0\). If light of frequency \(4\nu_0\) is incident on this metal, then the maximum kinetic energy of emitted electrons will be \(.......h\nu_0\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(( KE )_{\max }= hv - h v_{ Th }\) \(( KE )_{\max }= h \left(4 v_0\right)- hv_{0 }\)
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