NEET · Physics · STD 12 - 3. current electricity
The resistance of a wire is \(R\; ohm\). If it is melted and stretched to \('n'\) times its original length, its new resistance will be
- A \(\frac{R}{n}\)
- B \(n^2R\)
- C \(\;\frac{R}{{{n^2}}}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\)
- D \(nR\)
Answer & Solution
Correct Answer
(B) \(n^2R\)
Step-by-step Solution
Detailed explanation
The resistance of a wire of length \(l\) and area \(A\) and resistivity \(\rho\) is given as
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