NEET · Physics · STD 11 - 6. system of particles and rotational motion
The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is
- A \(\sqrt{2}: 1\)
- B \(4: 1\)
- C \(1: \sqrt{2}\)
- D \(2: 1\)
Answer & Solution
Correct Answer
(A) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
\(k =\sqrt{\frac{ I }{ m }}\) \(\Rightarrow \frac{ k _{1}}{ k _{2}}=\sqrt{\frac{ I _{1}}{ I _{2}}}=\sqrt{\frac{ mR ^{2} / 2}{ mR ^{2} / 4}}=\sqrt{2}: 1\)
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