NEET · Physics · STD 11 - 7. gravitation
The ratio of escape velocity at earth \((v_e)\) to the escape velocity at a planet \((v_p)\) whose radius and mean density are twice as that of earth is
- A \(1:2\)\(\sqrt 2 \)
- B \(1:4\)
- C \(1:\)\(\sqrt 2 \)
- D \(1:2\)
Answer & Solution
Correct Answer
(A) \(1:2\)\(\sqrt 2 \)
Step-by-step Solution
Detailed explanation
As escape velocity, \(v = \sqrt {\frac{{2GM}}{R}} \) \( = \sqrt {\frac{{2G}}{R}\frac{{4\pi {R^3}}}{3}\rho } = - R\sqrt {\frac{{8\pi G}}{3}\rho } \)
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