NEET · Physics · STD 12 - 1. Electric charges and fields
The ratio of coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is \(2.4 \times 10^{39}\). The ratio of the proportionality constant, \(K=\frac{1}{4 \pi \varepsilon_0}\) to the Gravitational constant \(G\) is nearly (Given that the charge of the proton and electron each \(=1.6 \times 10^{-19}\; C\), the mass of the electron \(=9.11 \times 10^{-31}\; kg\), the mass of the proton \(=1.67 \times 10^{-27}\,kg\) ):
- A \(10^{20}\)
- B \(10^{30}\)
- C \(10^{40}\)
- D \(10\)
Answer & Solution
Correct Answer
(A) \(10^{20}\)
Step-by-step Solution
Detailed explanation
\(\frac{ F _e}{ F _{ G }}=\frac{\frac{ Kq _1 q _2}{ r ^2}}{\frac{ Gm _1 m _2}{ r ^2}}\) \(2.4 \times 10^{39}=\frac{ K }{ G } \times \frac{\left(1.6 \times 10^{-19}\right)^2}{\left(9.11 \times 10^{-31} \times 1.67 \times 10^{-27}\right)}\)
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