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NEET · Physics · STD 12 - 13. Nuclei
The rate of radioactive disintegration at an instant for a radioactive sample of half life \(2.2 \times 10^9 \;s\) is \(10^{10}\; s ^{-1}\). The number of radioactive atoms in that sample at that instant is,
- A \(3.17 \times 10^{20}\)
- B \(3.17 \times 10^{19}\)
- C \(3.17 \times 10^{17}\)
- D \(3.17 \times 10^{18}\)
Answer & Solution
Correct Answer
(B) \(3.17 \times 10^{19}\)
Step-by-step Solution
Detailed explanation
\(T _{1 / 2}=\frac{\ln 2}{\lambda}=\frac{0.693}{\lambda}\) \(2.2 \times 10^9=\frac{0.693}{\lambda}\)
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