NEET · Physics · STD 12 - 9. Ray optics and optical instruments
The power of a biconvex lens is \(10\) dioptre and the radius of curvature of each surface is \(10 \;cm\). Then the refractive index of the material of the lens is,
- A \(\frac{3}{2}\)
- B \(\frac{4}{3}\)
- C \(\frac{9}{8}\)
- D \(\frac{5}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{3}{2}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)\) as \(P=\frac{1}{f(\text { in } m)}\)
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