NEET · Physics · STD 12 -7. Alternating current
The net impedance of circuit (as shown in figure) will be \(...........\,\Omega\)

- A \(15\)
- B \(10 \sqrt{2}\)
- C \(25\)
- D \(5 \sqrt{5}\)
Answer & Solution
Correct Answer
(D) \(5 \sqrt{5}\)
Step-by-step Solution
Detailed explanation
\(X_L =\frac{50}{ L } \times 10^{-3} \times 2 \pi \times 50=5\,\Omega\) \(X_C =\frac{1}{2 \pi \times 50 \times \frac{10^3}{\pi} \times 10^{-6}}=10\,\Omega\)
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