NEET · Physics · STD 11 - 6. system of particles and rotational motion
The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400 \mathrm{~g} \mathrm{~cm}^2\). The length of the \(400 \mathrm{~g}\) rod is nearly:
- A \(17.5 \mathrm{~cm}\)
- B \(20.7 \mathrm{~cm}\)
- C \(72.0 \mathrm{~cm}\)
- D \(8.5 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(8.5 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Moment of inertia of rod \(=l=\frac{m \ell^2}{12}\) \(\Rightarrow 2400=400 \frac{\ell^2}{12}\)
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