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NEET · Physics · STD 12 - 3. current electricity
The meter bridge shown is in balanced position with \(\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{l}_{1}}{\mathrm{l}_{2}}\). If we now litterchange the positions of gavanometer and cell, will the bridge work? If yes, what will be balance condition?

- A yes, \(\frac{\mathrm{P}}{\mathrm{Q}}=\frac{\mathrm{l}_{2}-\mathrm{l}_{1}}{\mathrm{l}_{2}+\mathrm{l}_{1}}\)
- B no, no null point
- C yes, \(\frac{P}{Q}=\frac{l_{2}}{l_{1}}\)
- D yes, \(\frac{P}{Q}=\frac{l_{1}}{l_{2}}\)
Answer & Solution
Correct Answer
(D) yes, \(\frac{P}{Q}=\frac{l_{1}}{l_{2}}\)
Step-by-step Solution
Detailed explanation
Interchanging cell and galvanometer do not effect balance condition.
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