NEET · Physics · STD 12 - 4. Moving charges and magnetism
The magnetic field on the axis of a circular loop of radius \(100\,cm\) carrying current \(I=\sqrt{2}\,A\), at point \(1\,m\) away from the centre of the loop is given by
- A \(3.14 \times 10^{-7}\,T\)
- B \(6.28 \times 10^{-7}\,T\)
- C \(3.14 \times 10^{-4}\,T\)
- D \(6.28 \times 10^{-4}\,T\)
Answer & Solution
Correct Answer
(A) \(3.14 \times 10^{-7}\,T\)
Step-by-step Solution
Detailed explanation
\(B _{ A }= B _0 \sin ^3 \theta\) \(=\frac{\mu_0 i }{2 R } \times \sin ^3 \theta\)
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