NEET · Physics · STD 12 - 10. Wave optics
The intensity of transmitted light when a polaroid sheet, placed between two crossed polaroids at \(22.5^{\circ}\) from the polarization axis of one of the polaroid, is ( \(I _0\) is the intensity of polarised light after passing through the first polaroid):
- A \(\frac{\text{I} _\text{0}}{2}\)
- B \(\frac{\text{I} _\text{0}}{4}\)
- C \(\frac{\text{I} _\text{0}}{8}\)
- D \(\frac{\text{I} _\text{0}}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{\text{I} _\text{0}}{8}\)
Step-by-step Solution
Detailed explanation
Initially two polaroids are crossed i.e. \(90^{\circ}\)
After passing from first polaroid intensity is \(\text I _0\)
\(\begin{array}{l}\Rightarrow \frac{ I _0}{4} \sin ^2(2 \theta) \\ \Rightarrow \frac{ I _0}{4} \sin ^2(2 \times 22.5) \\ \Rightarrow \frac{ I _0}{8}\end{array}\)
After passing from first polaroid intensity is \(\text I _0\)
\(\begin{array}{l}\Rightarrow \frac{ I _0}{4} \sin ^2(2 \theta) \\ \Rightarrow \frac{ I _0}{4} \sin ^2(2 \times 22.5) \\ \Rightarrow \frac{ I _0}{8}\end{array}\)
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