NEET · Physics · STD 12 - 13. Nuclei
The half-life of a radioactive nuclide is \(100 \,hours.\) The fraction of original activity that will remain after \(150\, hours\) would be :
- A \(\frac{1}{2}\)
- B \(\frac{1}{2 \sqrt{2}}\)
- C \(\frac{2}{3}\)
- D \(\frac{2}{3 \sqrt{2}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{A}{A_{0}}=\left(\frac{1}{2}\right)^{\mathrm{t} / T_{\mathrm{H}}}=\left(\frac{1}{2}\right)^{150 / 100}=\frac{1}{2 \sqrt{2}}\)
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