NEET · Physics · STD 11 - 5. work,energy,power and collision
The energy that will be ideally radiated by a \(100\,kW\) transmitter in \(1\) hour is :
- A \(36 \times 10^{4}\,J\)
- B \(36 \times 10^{5}\,J\)
- C \(1 \times 10^{5}\,J\)
- D \(36 \times 10^{7}\,J\)
Answer & Solution
Correct Answer
(D) \(36 \times 10^{7}\,J\)
Step-by-step Solution
Detailed explanation
\(E=P \times t=100 \times 10^{3} \times 3600\) \(=36 \times 10^{7}\,J\)
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