NEET · Physics · STD 12 - 14. Semicondutor electronics
The electron concentration in an \(n-\)type semiconductor is the same as hole concentration in a \(p-\)type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
- A current in \(\mathrm{n}\)-type \(=\) current in \(\mathrm{p}\)-type.
- B current in \(p-\)type \(>\) current in \(\mathrm{n}\)-type.
- C current in \(\mathrm{n}\)-type \(>\) current in \(\mathrm{p}\)-type.
- D No current will flow in \(p\)-type, current will only flow in \(\mathrm{n}\)-type.
Answer & Solution
Correct Answer
(C) current in \(\mathrm{n}\)-type \(>\) current in \(\mathrm{p}\)-type.
Step-by-step Solution
Detailed explanation
In \(N\) type semiconductor majority charge carriersare \(\mathrm{e}^{-}\)and \(\mathrm{P}\) type semiconductor majority chargecarriers are holes. \(I=\operatorname{neAV}_{d}=\operatorname{neA}(\mu \mathrm{E})\)
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