NEET · Physics · STD 12 - 8. Electromagnetic waves
The electric field in a plane electromagnetic wave is given by
\( E_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) V / m \)
Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :
- A \(B_y=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right)T\)
- B \(B_x=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right)T\)
- C \(B_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) T\)
- D \(B_y=60 \sin \left(5 x+1.5 \times 10^9 t\right) T\)
Answer & Solution
Correct Answer
(A) \(B_y=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right)T\)
Step-by-step Solution
Detailed explanation
\(v =\frac{\omega}{ k }=\frac{1.5 \times 10^9}{5}=3 \times 10^8 m / s\)
\(B _0=\frac{ F _0}{ v }=\frac{60}{3 \times 10^8}=20 \times 10^{-8}=2 \times 10^{-7} T\)
\(B _{ y }=2 \times 10^{-7} \cos \left(5 x +1.5 \times 10^9 t \right) T\)
\(B _0=\frac{ F _0}{ v }=\frac{60}{3 \times 10^8}=20 \times 10^{-8}=2 \times 10^{-7} T\)
\(B _{ y }=2 \times 10^{-7} \cos \left(5 x +1.5 \times 10^9 t \right) T\)
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