NEET · Physics · STD 12 - 2. Electric potential and capacitance
The distance between the two plates of a parallel plate capacitor is doubled and the area of each plate is halved. If \(C\) is its initial capacitance, its final capacitance is equal to
- A \(2 C\)
- B \(C / 2\)
- C \(4 C\)
- D \(C / 4\)
Answer & Solution
Correct Answer
(D) \(C / 4\)
Step-by-step Solution
Detailed explanation
\(C=\frac{\varepsilon_0 A}{d}\) Now, \(C^{\prime}=\frac{\varepsilon_0( A / 2)}{2 d }=\frac{\varepsilon_0 A }{4 d }=\frac{ C }{4}\)
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