NEET · Physics · STD 12 - 14. Semicondutor electronics
The collector current in a common base amplifier using \(n-p-n\) transistor is \(24\; mA\). If \(80 \%\) of the electrons released by the emitter is accepted by the collector, then the base current is numerically
- A \(6\,mA\) and leaving the base
- B \(3\,mA\) and leaving the base
- C \(6\,mA\) and entering the base
- D \(3\,mA\) and entering the base
Answer & Solution
Correct Answer
(C) \(6\,mA\) and entering the base
Step-by-step Solution
Detailed explanation
\(I _C=24\,mA\) \(\text { and } I _{ E }=\frac{ I _{ C }}{\alpha}\)
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