NEET · Physics · STD 12 - 3. current electricity
The charge flowing through a resistance \(R\) varies with time \(t\) as \( Q=at-bt^2 \) where \(a\) and \(b\) are positive constants . The total heat produced in \(R\) is
- A \(\frac{{{a^3}R}}{{3b}}\)
- B \(\;\frac{{{a^3}R}}{{2b}}\)
- C \(\;\frac{{{a^3}R}}{b}\)
- D \(\;\frac{{{a^3}R}}{{6b}}\)
Answer & Solution
Correct Answer
(D) \(\;\frac{{{a^3}R}}{{6b}}\)
Step-by-step Solution
Detailed explanation
\(\text { Given, } Q=a t-b t^{2}\) \(\therefore \quad I=\frac{d Q}{d t}=a-2 b t\)
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