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NEET · Physics · STD 11 - 3.2 motion in plane

The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is :

  1. A 900
  2. B 600
  3. C 150
  4. D 300
Verified Solution

Answer & Solution

Correct Answer

(C) 150

Step-by-step Solution

Detailed explanation

(C) 150
Initial angular speed, \(\omega_0=\frac{600 \times 2 \pi}{60}=20 \pi\ rad / s\)
Final angular speed, \(\omega=\frac{1200 \times 2 \pi}{60}=40 \pi\ rad / s\)
Angular acceleration, \(\alpha=\frac{\omega-\omega_0}{t}=\frac{40 \pi-20 \pi}{10}=2 \pi\ rad / s ^2\)
Angular displacement, \(\theta=\omega_0 t+\frac{1}{2} \alpha t^2\)
\(\theta=20 \pi \times 10+\frac{1}{2} \times 2 \pi \times(10)^2=200 \pi+100 \pi=300 \pi\ rad\)
Number of revolutions, \(N=\frac{\theta}{2 \pi}=\frac{300 \pi}{2 \pi}=150\)