NEET · Physics · STD 11 - 7. gravitation
The acceleration due to gravity at a height \(1\, km\) above the earth is the same as at a depth \(d\) below the surface of earth. Then \(d\,=\) ......... \(km\)
- A \(\frac{4}{3}\)
- B \(\;\frac{3}{2}\)
- C \(\;\frac{2}{3}\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
The acceleration due to gravity at a height \(h\) is given as \({g_h} = g\left( {1 - \frac{{2h}}{{{R_e}}}} \right)\)
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