NEET · Physics · STD 12 - 13. Nuclei
Radioactive material \('A'\) has decay constant \(8 \lambda\) and material \('B'\) has decay constant \( ' \lambda '\). Initially they have same number of nuclei . After what time, the ratio of number of nuclei of material \('B'\) to that \('A'\) will be \(\frac{1}{e}\) ?
- A \(\frac{1}{{\lambda }}\)
- B \(\frac{1}{{9\lambda }}\)
- C \(\frac{1}{{8\lambda }}\)
- D \(\frac{1}{{7\lambda }}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{{7\lambda }}\)
Step-by-step Solution
Detailed explanation
The number of radioactive nuclei \('N'\) at any time \(t\) is given as \(N(t)=N_{0} e^{-\lambda t}\)
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