NEET · Physics · STD 12 - 10. Wave optics
In Young's double slit experiment the separation \(d\) between the slits is \(2\,\, mm,\) the wavelength \(\lambda\) of the light used is \(5896 Å \) and distance \(D\) between the screen and slits is \(100\,\, cm.\) It is found that the angular width of the fringes is \(0.20^o \) . To increase the fringe angular width to \(0.21 ^o \) (with same \(\lambda\) and \(D\)) the separation between the slits needs to be changed to ......\(mm\)
- A \(1.8 \)
- B \(1.9\)
- C \(1.7\)
- D \(2.1\)
Answer & Solution
Correct Answer
(B) \(1.9\)
Step-by-step Solution
Detailed explanation
Angular width \(=\frac{\lambda}{d}\) \({0.20^\circ } = \frac{\lambda }{{2\,{\text{mm}}}}\) .... \((i)\) and \({0.21^\circ } = \frac{\lambda }{d}\) ..... \((ii)\)
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