NEET · Physics · STD 12 - 10. Wave optics
In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:
- A one\(-\)fourth
- B double
- C half
- D four times
Answer & Solution
Correct Answer
(D) four times
Step-by-step Solution
Detailed explanation
\(\beta=\frac{\lambda D}{d}\) \(\beta^{\prime}=\frac{\lambda D^{\prime}}{d^{\prime}}\)
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