NEET · Physics · STD 11 - 4.1 newtons laws of motion
In the diagram shown, the normal reaction force between \(2\,kg\) and \(1\,kg\) is (Consider the surface, to be smooth)\(.........N\) (Given \(g =10\,ms ^{-2}\))

- A \(25\)
- B \(39\)
- C \(6\)
- D \(10\)
Answer & Solution
Correct Answer
(A) \(25\)
Step-by-step Solution
Detailed explanation
\(a =\frac{\text { Net force }}{\text { Total mass }}=\frac{60-\left(18+60 \sin 30^{\circ}\right)}{6}=2\,ms ^{-2}\) \(FBD\) of \(1\,kg\)
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