NEET · Physics · STD 12 -6. Electromagnetic induction
In the above diagram, a strong bar magnet is moving towards solenoid-\(2\) from solenoid-\(1\). The direction of induced current in solenoid-\(1\) and that in solenoid-\(2\), respectively, are through the directions:
- A \(B A\) and \(C D\)
- B \(A B\) and \(C D\)
- C \(B A\) and \(D C\)
- D \(A B\) and \(D C\)
Answer & Solution
Correct Answer
(D) \(A B\) and \(D C\)
Step-by-step Solution
Detailed explanation
North of magnet is moving away from solenoid \(1\) so end \(B\) of solenoid \(1\) is South and as south of magnet is approaching solenoid \(2\) so end \(C\) of solenoid \(2\) is South.
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